C-09-Q044mediumsingle_mcqtanθ=sinθ?\tan\theta = \dfrac{\sin\theta}{?}tanθ=?sinθacosθ\cos\thetacosθbsinθ\sin\thetasinθctanθ\tan\thetatanθdsecθ\sec\thetasecθব্যাখ্যাSince sinθ=opphyp\sin\theta=\dfrac{\text{opp}}{\text{hyp}}sinθ=hypopp and cosθ=adjhyp\cos\theta=\dfrac{\text{adj}}{\text{hyp}}cosθ=hypadj, dividing gives sinθcosθ=oppadj=tanθ\dfrac{\sin\theta}{\cos\theta}=\dfrac{\text{opp}}{\text{adj}}=\tan\thetacosθsinθ=adjopp=tanθ. Hence the denominator is cosθ\cos\thetacosθ.