C-09-Q033mediumsingle_mcqsecθ=?\sec\theta = ?secθ=?a1sinθ\dfrac{1}{\sin\theta}sinθ1b1cosθ\dfrac{1}{\cos\theta}cosθ1c1tanθ\dfrac{1}{\tan\theta}tanθ1dsinθcosθ\dfrac{\sin\theta}{\cos\theta}cosθsinθব্যাখ্যাSecant is the reciprocal of cosine, so secθ=1cosθ=hypotenuseadjacent\sec\theta=\dfrac{1}{\cos\theta}=\dfrac{\text{hypotenuse}}{\text{adjacent}}secθ=cosθ1=. Thus .