C-12-Q065mediumsingle_mcq

The solution $(x, y)$ of $2x + 3y + 5 = 0,\; 4x + 7y + 6 = 0$ is —

a $\left(-\dfrac{17}{2},\; 4\right)$
b $\left(\dfrac{17}{2},\; -4\right)$
c $\left(-4,\; \dfrac{17}{2}\right)$
d $(2, -3)$

ব্যাখ্যা

Multiplying $2x+3y+5=0$ by $2$ and subtracting from $4x+7y+6=0$ eliminates $x$ and gives $y-4=0$ , so $y=4$ . Then $2x+12+5=0$ gives $x=-\dfrac{17}{2}$ .

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Simple Simultaneous Equations in Two Variables — সব প্রশ্ন দেখুন (152টি) →

The solution $(x, y)$ of $2x + 3y + 5 = 0,\; 4x + 7y + 6 = 0$ is —

\left(-\dfrac{17}{2},\; 4\right)

\left(\dfrac{17}{2},\; -4\right)

\left(-4,\; \dfrac{17}{2}\right)

(2, -3)

ব্যাখ্যা

Multiplying $2x+3y+5=0$ by $2$ and subtracting from $4x+7y+6=0$ eliminates $x$ and gives $y-4=0$ , so $y=4$ . Then $2x+12+5=0$ gives $x=-\dfrac{17}{2}$ .

The solution (x,y)(x, y)(x,y) of 2x+3y+5=0, 4x+7y+6=02x + 3y + 5 = 0,\; 4x + 7y + 6 = 02x+3y+5=0,4x+7y+6=0 is —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The solution (x,y)(x, y)(x,y) of 2x+3y+5=0, 4x+7y+6=02x + 3y + 5 = 0,\; 4x + 7y + 6 = 02x+3y+5=0,4x+7y+6=0 is —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The solution $(x, y)$ of $2x + 3y + 5 = 0,\; 4x + 7y + 6 = 0$ is —

The solution $(x, y)$ of $2x + 3y + 5 = 0,\; 4x + 7y + 6 = 0$ is —