C-12-Q064mediumsingle_mcq

The solution $(x, y)$ of $ax - by = ab = bx - ay$ is —

a $\left(\dfrac{ab}{a + b},\; \dfrac{ab}{a + b}\right)$
b $\left(\dfrac{ab}{a + b},\; -\dfrac{ab}{a + b}\right)$
c $(a, b)$
d $(a - b,\; a + b)$

ব্যাখ্যা

Subtracting the two equations $ax-by=ab$ and $bx-ay=ab$ yields $(a-b)(x+y)=0$ , so $x+y=0$ , i.e. $y=-x$ . Substituting back gives $x(a+b)=ab$ , hence $x=\dfrac{ab}{a+b}$ and $y=-\dfrac{ab}{a+b}$ .

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Simple Simultaneous Equations in Two Variables — সব প্রশ্ন দেখুন (152টি) →

The solution $(x, y)$ of $ax - by = ab = bx - ay$ is —

\left(\dfrac{ab}{a + b},\; \dfrac{ab}{a + b}\right)

\left(\dfrac{ab}{a + b},\; -\dfrac{ab}{a + b}\right)

(a, b)

(a - b,\; a + b)

ব্যাখ্যা

Subtracting the two equations $ax-by=ab$ and $bx-ay=ab$ yields $(a-b)(x+y)=0$ , so $x+y=0$ , i.e. $y=-x$ . Substituting back gives $x(a+b)=ab$ , hence $x=\dfrac{ab}{a+b}$ and $y=-\dfrac{ab}{a+b}$ .

The solution (x,y)(x, y)(x,y) of ax−by=ab=bx−ayax - by = ab = bx - ayax−by=ab=bx−ay is —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The solution (x,y)(x, y)(x,y) of ax−by=ab=bx−ayax - by = ab = bx - ayax−by=ab=bx−ay is —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The solution $(x, y)$ of $ax - by = ab = bx - ay$ is —

The solution $(x, y)$ of $ax - by = ab = bx - ay$ is —