The solution of $x + 2y = 7,\; 2x - 3y = 0$ is —

From $2x-3y=0$ we get $x=\dfrac{3y}{2}$; substituting into $x+2y=7$ gives $\dfrac{7y}{2}=7$, so $y=2$ and $x=3$. The solution is $(3,2)$.