C-12-Q068mediumsingle_mcq

The solution of $x + 2y = 7,\; 2x - 3y = 0$ is —

From $2x-3y=0$ we get $x=\dfrac{3y}{2}$ ; substituting into gives , so and . The solution is .

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(1, 3)

(3, 1)

x+2y=7

\dfrac{7y}{2}=7

y=2

x=3

(3,2)

C-12-Q077