C-12-Q055mediumsingle_mcq

By cross-multiplication, for $a_1 x + b_1 y + c_1 = 0,\; a_2 x + b_2 y + c_2 = 0$ , the value of $x$ is —

a $\dfrac{b_1 c_2 - b_2 c_1}{a_1 b_2 - a_2 b_1}$
b $\dfrac{c_1 a_2 - c_2 a_1}{a_1 b_2 - a_2 b_1}$
c $\dfrac{a_1 b_2 - a_2 b_1}{b_1 c_2 - b_2 c_1}$
d $\dfrac{b_1 c_2 - b_2 c_1}{c_1 a_2 - c_2 a_1}$

ব্যাখ্যা

By the standard cross-multiplication formula for $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ , the relation is $\dfrac{x}{b_1c_2 - b_2c_1} = \dfrac{1}{a_1b_2 - a_2b_1}$ , giving $x = \dfrac{b_1c_2 - b_2c_1}{a_1b_2 - a_2b_1}$ .

এই অধ্যায়ের আরও প্রশ্ন

C-12-Q056By cross-multiplication, the value of is —
C-12-Q057In the cross-multiplication formula, the expression appears as —
C-12-Q058Before applying cross-multiplication the equations must be expressed in the form —
C-12-Q059In , the values of respectively are —
C-12-Q060In , the values of respectively are —
C-12-Q061The solution of by cross-multiplication is —
C-12-Q062The solution of by cross-multiplication is —
C-12-Q063The solution of is —
C-12-Q064The solution of is —
C-12-Q065The solution of is —

Simple Simultaneous Equations in Two Variables — সব প্রশ্ন দেখুন (152টি) →

By cross-multiplication, for $a_1 x + b_1 y + c_1 = 0,\; a_2 x + b_2 y + c_2 = 0$ , the value of $x$ is —

\dfrac{b_1 c_2 - b_2 c_1}{a_1 b_2 - a_2 b_1}

\dfrac{c_1 a_2 - c_2 a_1}{a_1 b_2 - a_2 b_1}

\dfrac{a_1 b_2 - a_2 b_1}{b_1 c_2 - b_2 c_1}

\dfrac{b_1 c_2 - b_2 c_1}{c_1 a_2 - c_2 a_1}

By cross-multiplication, for a1x+b1y+c1=0, a2x+b2y+c2=0a_1 x + b_1 y + c_1 = 0,\; a_2 x + b_2 y + c_2 = 0a1​x+b1​y+c1​=0,a2​x+b2​y+c2​=0, the value of xxx is —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

By cross-multiplication, for a1x+b1y+c1=0, a2x+b2y+c2=0a_1 x + b_1 y + c_1 = 0,\; a_2 x + b_2 y + c_2 = 0a1​x+b1​y+c1​=0,a2​x+b2​y+c2​=0, the value of xxx is —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

By cross-multiplication, for $a_1 x + b_1 y + c_1 = 0,\; a_2 x + b_2 y + c_2 = 0$ , the value of $x$ is —

By cross-multiplication, for $a_1 x + b_1 y + c_1 = 0,\; a_2 x + b_2 y + c_2 = 0$ , the value of $x$ is —