C-14-Q072mediumsingle_mcq

In the proof, $\triangle ABC$ and $\triangle APQ$ are equiangular because —

athey are congruent
b $PQ \parallel BC$
c $PQ = BC$
dthey share the same circumcircle

ব্যাখ্যা

Since $PQ \parallel BC$ , the corresponding angles formed with the transversals $AB$ and $AC$ are equal, making $\angle APQ = \angle ABC$ and $\angle AQP = \angle ACB$ ; hence the two triangles are equiangular.

এই অধ্যায়ের আরও প্রশ্ন

C-14-Q073Theorem 33 is the converse of —
C-14-Q074If one angle of a triangle equals an angle of another and the sides adjacent to those angles are proportional,
C-14-Q075In the proof of Theorem 34, by —
C-14-Q076After establishing , we conclude —
C-14-Q077Theorem 34 is the analogue, for similarity, of —
C-14-Q078The ratio of the areas of two similar triangles equals the ratio of the squares of —
C-14-Q079If , then
C-14-Q080with , . The ratio of areas is —
C-14-Q081Two similar triangles have areas in ratio . The ratio of matching sides is —
C-14-Q082with , , area of . Area of

In the proof, $\triangle ABC$ and $\triangle APQ$ are equiangular because —

athey are congruent

PQ \parallel BC

PQ = BC

dthey share the same circumcircle

In the proof, △ABC\triangle ABC△ABC and △APQ\triangle APQ△APQ are equiangular because —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In the proof, △ABC\triangle ABC△ABC and △APQ\triangle APQ△APQ are equiangular because —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In the proof, $\triangle ABC$ and $\triangle APQ$ are equiangular because —

In the proof, $\triangle ABC$ and $\triangle APQ$ are equiangular because —