C-14-Q082mediumsingle_mcq△ABC∼△DEF\triangle ABC \sim \triangle DEF△ABC∼△DEF with AB=6AB = 6AB=6, DE=9DE = 9DE=9, area of △ABC=24\triangle ABC = 24△ABC=24. Area of △DEF=?\triangle DEF = ?△DEF=?a363636b484848c545454d727272ব্যাখ্যাThe side ratio is 69=23\dfrac{6}{9} = \dfrac{2}{3}96=32, so the area ratio is 49\dfrac{4}{9}94; thus area of △DEF=24×94=54\triangle DEF = 24 \times \dfrac{9}{4} = 54△DEF=24×49=54.