C-14-Q079: If $\triangle ABC \sim \triangle DEF$, then $\dfrac{\triangle ABC}{\tr… | প্রশ্ন করি

হোম›নবম-দশম শ্রেণি›English Version›Mathematics›Ratio, Similarity and Symmetry›C-14-Q079

C-14-Q079mediumsingle_mcq

If $\triangle ABC \sim \triangle DEF$ , then $\dfrac{\triangle ABC}{\triangle DEF} = ?$

a $\dfrac{BC}{EF}$
b $\dfrac{BC^{2}}{EF^{2}}$

ব্যাখ্যা

The ratio of areas of similar triangles equals the square of the ratio of corresponding sides, so $\dfrac{\triangle ABC}{\triangle DEF} = \dfrac{BC^2}{EF^2}$ .

79/160

এই অধ্যায়ের আরও প্রশ্ন

C-14-Q080with , . The ratio of areas is —
C-14-Q081Two similar triangles have areas in ratio . The ratio of matching sides is —
C-14-Q082with , , area of . Area of
C-14-Q083In the proof of Theorem 35,
C-14-Q084Two similar triangles with matching side ratio have area ratio —
C-14-Q085If areas of two similar triangles are and , the ratio of matching sides is —
C-14-Q086If lies between and with , then divides —
C-14-Q087Construction 12 divides a segment in a given internal ratio using a parallel line whose existence relies on —
C-14-Q088In Construction 12, on ray we cut and . Drawing gives —

EF2BC2

\dfrac{BC^{3}}{EF^{3}}

\dfrac{EF^{2}}{BC^{2}}

EF2BC2

C-14-Q089Example 1: a cm segment is divided in the ratio . The two parts measure —

If △ABC∼△DEF\triangle ABC \sim \triangle DEF△ABC∼△DEF, then △ABC△DEF=?\dfrac{\triangle ABC}{\triangle DEF} = ?△DEF△ABC​=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

If $\triangle ABC \sim \triangle DEF$ , then $\dfrac{\triangle ABC}{\triangle DEF} = ?$