C-14-Q066mediumsingle_mcq

For $\triangle ABC \sim \triangle DEF$ with $\angle A = \angle D$ , $\angle B = \angle E$ , $\angle C = \angle F$ —

a $\dfrac{AB}{DE} = \dfrac{AC}{DF} = \dfrac{BC}{EF}$
b $AB = DE$
c $\dfrac{AB}{DF} = \dfrac{AC}{DE}$
d $\dfrac{AB}{EF} = \dfrac{BC}{DE}$

ব্যাখ্যা

Since $\triangle ABC \sim \triangle DEF$ , corresponding sides are in a constant ratio. This gives $\dfrac{AB}{DE} = \dfrac{AC}{DF} = \dfrac{BC}{EF}$ , pairing sides opposite equal angles.

এই অধ্যায়ের আরও প্রশ্ন

C-14-Q067In the proof of Theorem 32, by —
C-14-Q068After , we get , hence —
C-14-Q069The relation in the proof follows from —
C-14-Q070If three pairs of corresponding sides of two triangles are proportional, the corresponding angles are —
C-14-Q071In the proof of Theorem 33, by —
C-14-Q072In the proof, and are equiangular because —
C-14-Q073Theorem 33 is the converse of —
C-14-Q074If one angle of a triangle equals an angle of another and the sides adjacent to those angles are proportional,
C-14-Q075In the proof of Theorem 34, by —
C-14-Q076After establishing , we conclude —

For $\triangle ABC \sim \triangle DEF$ with $\angle A = \angle D$ , $\angle B = \angle E$ , $\angle C = \angle F$ —

\dfrac{AB}{DE} = \dfrac{AC}{DF} = \dfrac{BC}{EF}

AB = DE

\dfrac{AB}{DF} = \dfrac{AC}{DE}

\dfrac{AB}{EF} = \dfrac{BC}{DE}

ব্যাখ্যা

Since $\triangle ABC \sim \triangle DEF$ , corresponding sides are in a constant ratio. This gives $\dfrac{AB}{DE} = \dfrac{AC}{DF} = \dfrac{BC}{EF}$ , pairing sides opposite equal angles.

For △ABC∼△DEF\triangle ABC \sim \triangle DEF△ABC∼△DEF with ∠A=∠D\angle A = \angle D∠A=∠D, ∠B=∠E\angle B = \angle E∠B=∠E, ∠C=∠F\angle C = \angle F∠C=∠F —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

For △ABC∼△DEF\triangle ABC \sim \triangle DEF△ABC∼△DEF with ∠A=∠D\angle A = \angle D∠A=∠D, ∠B=∠E\angle B = \angle E∠B=∠E, ∠C=∠F\angle C = \angle F∠C=∠F —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

For $\triangle ABC \sim \triangle DEF$ with $\angle A = \angle D$ , $\angle B = \angle E$ , $\angle C = \angle F$ —

For $\triangle ABC \sim \triangle DEF$ with $\angle A = \angle D$ , $\angle B = \angle E$ , $\angle C = \angle F$ —