C-14-Q068: After $\triangle APQ \cong \triangle DEF$, we get $\angle APQ = \angle… | প্রশ্ন করি

হোম›নবম-দশম শ্রেণি›English Version›Mathematics›Ratio, Similarity and Symmetry›C-14-Q068

C-14-Q068mediumsingle_mcq

After $\triangle APQ \cong \triangle DEF$ , we get $\angle APQ = \angle ABC$ , hence —

a $PQ \perp BC$
b $PQ \parallel BC$
c

ব্যাখ্যা

The congruence gives $\angle APQ = \angle DEF = \angle ABC$ . Since these are equal corresponding angles on line $AB$ cut by $PQ$ and , the lines and are parallel.

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এই অধ্যায়ের আরও প্রশ্ন

C-14-Q069The relation in the proof follows from —
C-14-Q070If three pairs of corresponding sides of two triangles are proportional, the corresponding angles are —
C-14-Q071In the proof of Theorem 33, by —
C-14-Q072In the proof, and are equiangular because —
C-14-Q073Theorem 33 is the converse of —
C-14-Q074If one angle of a triangle equals an angle of another and the sides adjacent to those angles are proportional,
C-14-Q075In the proof of Theorem 34, by —
C-14-Q076After establishing , we conclude —
C-14-Q077Theorem 34 is the analogue, for similarity, of —

PQ = BC

PQ = \dfrac{1}{2} BC

BC

PQ

BC

C-14-Q078The ratio of the areas of two similar triangles equals the ratio of the squares of —

After △APQ≅△DEF\triangle APQ \cong \triangle DEF△APQ≅△DEF, we get ∠APQ=∠ABC\angle APQ = \angle ABC∠APQ=∠ABC, hence —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

After $\triangle APQ \cong \triangle DEF$ , we get $\angle APQ = \angle ABC$ , hence —