C-14-Q010mediumsingle_mcq

Componendo and dividendo together give —

a $\dfrac{a-b}{a+b} = \dfrac{c+d}{c-d}$
b $\dfrac{a+b}{a-b} = \dfrac{c+d}{c-d}$
c $\dfrac{a+b}{a-b} = \dfrac{c-d}{c+d}$
d $\dfrac{a+b}{b} = \dfrac{c-d}{d}$

ব্যাখ্যা

Componendo adds the denominators to numerators ( $\frac{a+b}{b}=\frac{c+d}{d}$ ) and dividendo subtracts them ( $\frac{a-b}{b}=\frac{c-d}{d}$ ); dividing the first by the second cancels $b$ and $d$ to give $\frac{a+b}{a-b}=\frac{c+d}{c-d}$ . This combined transformation is the standard componendo-dividendo result.

এই অধ্যায়ের আরও প্রশ্ন

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Componendo and dividendo together give —

\dfrac{a-b}{a+b} = \dfrac{c+d}{c-d}

\dfrac{a+b}{a-b} = \dfrac{c+d}{c-d}

\dfrac{a+b}{a-b} = \dfrac{c-d}{c+d}

\dfrac{a+b}{b} = \dfrac{c-d}{d}