C-14-Q009mediumsingle_mcq

By dividendo, if $a:b = x:y$ , then —

a $a-b : b = x-y : y$
b $a-b : a = x-y : x$
c $a-b : b = x+y : y$
d $b-a : b = y-x : y$

ব্যাখ্যা

Dividendo subtracts the denominator from the numerator on each side: from $\frac{a}{b} = \frac{x}{y}$ we get $\frac{a-b}{b} = \frac{x-y}{y}$ , i.e. $a-b : b = x-y : y$ . Subtracting $1$ from both equal fractions keeps them equal.

এই অধ্যায়ের আরও প্রশ্ন

C-14-Q010Componendo and dividendo together give —
C-14-Q011If , then
C-14-Q012If , then
C-14-Q013Applying inversendo on gives —
C-14-Q014Applying alternendo on gives —
C-14-Q015If two triangles have equal heights, their areas are proportional to their —
C-14-Q016If two triangles have equal bases, their areas are proportional to their —
C-14-Q017The area of a triangle equals —
C-14-Q018Triangles and have equal heights , and bases , . Then
C-14-Q019Triangles with equal bases and heights , have area ratio —

By dividendo, if $a:b = x:y$ , then —

a-b : b = x-y : y

a-b : a = x-y : x

a-b : b = x+y : y

b-a : b = y-x : y

By dividendo, if a:b=x:ya:b = x:ya:b=x:y, then —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

By dividendo, if a:b=x:ya:b = x:ya:b=x:y, then —

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

By dividendo, if $a:b = x:y$ , then —

By dividendo, if $a:b = x:y$ , then —