C-07-Q058mediumsingle_mcq

At $O$ the angle $\angle AOP$ is constructed equal to—

a $\angle x$
b $\angle y$
ca right angle
d $\angle ABO$

ব্যাখ্যা

At $O$ the angle $\angle AOP$ is constructed equal to the given angle $\angle x$ , reproducing the required angle between the diagonals at their point of intersection.

এই অধ্যায়ের আরও প্রশ্ন

C-07-Q059From and , segments and are cut each equal to—
C-07-Q060In and , equals—
C-07-Q061The congruence uses—
C-07-Q062From being alternate angles, it follows that—
C-07-Q063In Construction 4, the included angle between the diagonals is—
C-07-Q064In Construction 5, on ray the segment is cut equal to—
C-07-Q065The arcs at and are drawn with radii respectively—
C-07-Q066The point of intersection of these arcs gives—
C-07-Q067To complete the parallelogram, is cut from equal to—
C-07-Q068In Construction 5, is justified by—

Practical Geometry — সব প্রশ্ন দেখুন (150টি) →

At OOO the angle ∠AOP\angle AOP∠AOP is constructed equal to—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

At OOO the angle ∠AOP\angle AOP∠AOP is constructed equal to—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

At $O$ the angle $\angle AOP$ is constructed equal to—

At $O$ the angle $\angle AOP$ is constructed equal to—