C-07-Q068mediumsingle_mcq

In Construction 5, $\triangle AOB \cong \triangle COD$ is justified by—

aSSS
bSAS using equal half-diagonals and vertical angles
cASA
dRHS

ব্যাখ্যা

The half-diagonals give $OA = OC$ and $OB = OD$ , while $\angle AOB = \angle COD$ as vertically opposite angles. Two pairs of equal sides with the equal included angle yield congruence by SAS.

এই অধ্যায়ের আরও প্রশ্ন

C-07-Q069In Example 3 the parallel sides satisfy—
C-07-Q070From ray , the line segment is cut equal to—
C-07-Q071From line segment , is cut equal to—
C-07-Q072The line through parallel to meets ray at—
C-07-Q073The segment is drawn—
C-07-Q074Quadrilateral in Example 3 is a—
C-07-Q075The line segment is cut equal to—
C-07-Q076At , the angle constructed equals—
C-07-Q077At , the angle constructed equals—
C-07-Q078In Example 4, the rhombus to be constructed has each side equal to—

Practical Geometry — সব প্রশ্ন দেখুন (150টি) →

In Construction 5, $\triangle AOB \cong \triangle COD$ is justified by—

aSSS

bSAS using equal half-diagonals and vertical angles

cASA

dRHS

ব্যাখ্যা

The half-diagonals give $OA = OC$ and $OB = OD$ , while $\angle AOB = \angle COD$ as vertically opposite angles. Two pairs of equal sides with the equal included angle yield congruence by SAS.

In Construction 5, △AOB≅△COD\triangle AOB \cong \triangle COD△AOB≅△COD is justified by—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Construction 5, △AOB≅△COD\triangle AOB \cong \triangle COD△AOB≅△COD is justified by—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Construction 5, $\triangle AOB \cong \triangle COD$ is justified by—

In Construction 5, $\triangle AOB \cong \triangle COD$ is justified by—