C-07-Q061mediumsingle_mcq

The congruence $\triangle AOB \cong \triangle COD$ uses—

aSSS
bSAS
cASA
dAAS

ব্যাখ্যা

Here $OA = OC = \frac{a}{2}$ , $OB = OD = \frac{b}{2}$ , and $\angle AOB = \angle COD$ as vertically opposite angles. With two sides and the included angle equal, the triangles are congruent by the SAS criterion.

এই অধ্যায়ের আরও প্রশ্ন

C-07-Q062From being alternate angles, it follows that—
C-07-Q063In Construction 4, the included angle between the diagonals is—
C-07-Q064In Construction 5, on ray the segment is cut equal to—
C-07-Q065The arcs at and are drawn with radii respectively—
C-07-Q066The point of intersection of these arcs gives—
C-07-Q067To complete the parallelogram, is cut from equal to—
C-07-Q068In Construction 5, is justified by—
C-07-Q069In Example 3 the parallel sides satisfy—
C-07-Q070From ray , the line segment is cut equal to—
C-07-Q071From line segment , is cut equal to—

Practical Geometry — সব প্রশ্ন দেখুন (150টি) →

The congruence $\triangle AOB \cong \triangle COD$ uses—

aSSS

bSAS

cASA

dAAS

The congruence △AOB≅△COD\triangle AOB \cong \triangle COD△AOB≅△COD uses—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The congruence △AOB≅△COD\triangle AOB \cong \triangle COD△AOB≅△COD uses—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The congruence $\triangle AOB \cong \triangle COD$ uses—

The congruence $\triangle AOB \cong \triangle COD$ uses—