C-06-Q170mediumsingle_mcq

In a right triangle with the right angle at $B$ , if $D$ is the midpoint of hypotenuse $AC$ , then $BD =$

a $AC$
b $\tfrac{1}{2} AC$
c $2 AC$
d $\tfrac{1}{3} AC$

ব্যাখ্যা

In a right triangle, the midpoint of the hypotenuse is equidistant from all three vertices (it is the circumcentre). Therefore the median to the hypotenuse equals half the hypotenuse, $BD = \tfrac{1}{2}AC$ .

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Lines, Angles and Triangles — সব প্রশ্ন দেখুন (191টি) →

In a right triangle with the right angle at $B$ , if $D$ is the midpoint of hypotenuse $AC$ , then $BD =$

AC

\tfrac{1}{2} AC

2 AC

\tfrac{1}{3} AC

In a right triangle with the right angle at BBB, if DDD is the midpoint of hypotenuse ACACAC, then BD=BD =BD=

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In a right triangle with the right angle at BBB, if DDD is the midpoint of hypotenuse ACACAC, then BD=BD =BD=

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In a right triangle with the right angle at $B$ , if $D$ is the midpoint of hypotenuse $AC$ , then $BD =$

In a right triangle with the right angle at $B$ , if $D$ is the midpoint of hypotenuse $AC$ , then $BD =$