C-06-Q176mediumsingle_mcq

In Example 1, $AB = AC$ and $BA$ is produced to $D$ such that $AD = AC$ . Then $\angle BCD$ equals—

a $45°$
b $60°$
c $1$ right angle
d $120°$

ব্যাখ্যা

With $AB = AC = AD$ , point $A$ is equidistant from $B$ , $C$ , $D$ , so these points lie on a circle with $BD$ as diameter. The angle $\angle BCD$ inscribed in a semicircle is therefore a right angle.

এই অধ্যায়ের আরও প্রশ্ন

C-06-Q177In Example 1, the inequality proved is
C-06-Q178In Example 2, the three medians of meet at the point—
C-06-Q179Example 2 proves that
C-06-Q180Any point on the perpendicular bisector of a line segment is—
C-06-Q181In an isosceles triangle, the bisector of the vertical angle—
C-06-Q182If and are supplementary and , then
C-06-Q183In , right angle and is the midpoint of hypotenuse . Then
C-06-Q184The total number of medians in a triangle is—
C-06-Q185In , right angle and . Then
C-06-Q186Continuing the previous question, .

Lines, Angles and Triangles — সব প্রশ্ন দেখুন (191টি) →

In Example 1, $AB = AC$ and $BA$ is produced to $D$ such that $AD = AC$ . Then $\angle BCD$ equals—

45°

60°

1

right angle

120°

In Example 1, AB=ACAB = ACAB=AC and BABABA is produced to DDD such that AD=ACAD = ACAD=AC. Then ∠BCD\angle BCD∠BCD equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Example 1, AB=ACAB = ACAB=AC and BABABA is produced to DDD such that AD=ACAD = ACAD=AC. Then ∠BCD\angle BCD∠BCD equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Example 1, $AB = AC$ and $BA$ is produced to $D$ such that $AD = AC$ . Then $\angle BCD$ equals—

In Example 1, $AB = AC$ and $BA$ is produced to $D$ such that $AD = AC$ . Then $\angle BCD$ equals—