C-13-Q117mediumsingle_mcqThe number of terms in 12+24+48+⋯+76812 + 24 + 48 + \cdots + 76812+24+48+⋯+768 is —a777b666c888d999ব্যাখ্যাThe last term is 768=12⋅2n−1768=12\cdot 2^{n-1}768=12⋅2n−1, so 2n−1=64=262^{n-1}=64=2^{6}2n−1=64=26, giving n−1=6n-1=6n−1=6 and hence n=7n=7n=7 terms.