C-13-Q116mediumsingle_mcqThe sum 12+24+48+⋯+76812 + 24 + 48 + \cdots + 76812+24+48+⋯+768 is —a152415241524b150015001500c129612961296d102410241024ব্যাখ্যাHere a=12a=12a=12, r=2r=2r=2, and the last term 768=12⋅26768=12\cdot 2^{6}768=12⋅26 gives n=7n=7n=7. So S7=12(27−1)2−1=12⋅127=1524S_7=\dfrac{12(2^{7}-1)}{2-1}=12\cdot 127=1524S7=2−112(27−1)=12⋅127=1524.