C-04-Q046mediumsingle_mcq(13)−2=?\left(\dfrac{1}{3}\right)^{-2} = ?(31)−2=?a19\dfrac{1}{9}91b999c−9-9−9d−19-\dfrac{1}{9}−91ব্যাখ্যাA negative exponent inverts the base, so (13)−2=32=9\left(\dfrac{1}{3}\right)^{-2} = 3^2 = 9(31)−2=32=9.