C-04-Q049mediumsingle_mcq(23)5×(23)−5=?\left(\dfrac{2}{3}\right)^5 \times \left(\dfrac{2}{3}\right)^{-5} = ?(32)5×(32)−5=?a(23)25\left(\dfrac{2}{3}\right)^{25}(32)25b(23)−25\left(\dfrac{2}{3}\right)^{-25}(32)−25c111d000ব্যাখ্যাBy the product rule the exponents add: 5+(−5)=05 + (-5) = 05+(−5)=0, so (23)0=1\left(\dfrac{2}{3}\right)^{0} = 1(32)0=1.