C-04-Q052mediumsingle_mcqFor all integer m,nm, nm,n, aman=?\dfrac{a^m}{a^n} = ?anam=?aam+na^{m+n}am+nbam−na^{m-n}am−ncan−ma^{n-m}an−mdamna^{mn}amnব্যাখ্যাDividing powers of the same base subtracts the exponents, giving aman=am−n\dfrac{a^m}{a^n} = a^{m-n}anam=am−n.