C-04-Q040mediumsingle_mcqan+1an=?\dfrac{a^{n+1}}{a^n} = ?anan+1=?aaaaba2n+1a^{2n+1}a2n+1c111da−1a^{-1}a−1ব্যাখ্যাBy the quotient rule, an+1an=a(n+1)−n=a1=a\dfrac{a^{n+1}}{a^n} = a^{(n+1)-n} = a^1 = aanan+1=a(n+1)−n=a1=a.