C-04-Q029mediumsingle_mcq(ab)3a2b\dfrac{(ab)^3}{a^2 b}a2b(ab)3 equals—aab2ab^2ab2ba2b3a^2 b^3a2b3ca3b2a^3 b^2a3b2daba babব্যাখ্যাExpanding gives a3b3a2b=a3−2b3−1=ab2\dfrac{a^3 b^3}{a^2 b} = a^{3-2} b^{3-1} = a b^2a2ba3b3=a3−2b3−1=ab2. Subtracting exponents for each base yields ab2ab^2ab2.