C-04-Q034mediumsingle_mcqa7b3a4b5=?\dfrac{a^7 b^3}{a^4 b^5} = ?a4b5a7b3=?aa3b2\dfrac{a^3}{b^2}b2a3bব্যাখ্যাSubtracting exponents per base: a7−4b3−5=a3b−2=a3b2a^{7-4} b^{3-5} = a^3 b^{-2} = \dfrac{a^3}{b^2}a7−4b3−5=a. The negative power on moves it to the denominator.