C-05-Q122mediumsingle_mcqFrom (2 x+3)(3 x−2)=0(\sqrt{2}\, x + 3)(\sqrt{3}\, x - 2) = 0(2x+3)(3x−2)=0 the values of xxx are—a−32\dfrac{-3}{\sqrt{2}}2−3 or 23\dfrac{2}{\sqrt{3}}32b32\dfrac{3}{\sqrt{2}}23 or −23\dfrac{-2}{\sqrt{3}}3−2c2\sqrt{2}2 or 3\sqrt{3}3d−3-3−3 or 222ব্যাখ্যাBy the zero-product rule, either 2 x+3=0\sqrt{2}\,x+3=02x+3=0 giving x=−32x=\frac{-3}{\sqrt{2}}x=2−3, or 3 x−2=0\sqrt{3}\,x-2=03x−2=0 giving x=23x=\frac{2}{\sqrt{3}}x=32.