C-05-Q121mediumsingle_mcqSolve (y+5)(y−5)=24(y + 5)(y - 5) = 24(y+5)(y−5)=24:ay=±6y = \pm 6y=±6by=±7y = \pm 7y=±7cy=±5y = \pm 5y=±5dy=±24y = \pm 24y=±24ব্যাখ্যাUsing the difference of squares, (y+5)(y−5)=y2−25=24(y+5)(y-5)=y^2-25=24(y+5)(y−5)=y2−25=24, so y2=49y^2=49y2=49 and y=±7y=\pm7y=±7.