C-05-Q127mediumsingle_mcq

Solution set of $\dfrac{(x + 1)^3 - (x - 1)^3}{(x + 1)^2 - (x - 1)^2} = 1$ comes from—

asimplifying to $\dfrac{6x^2 + 2}{4x} = 1$ , then quadratic in $x$
blinear in $x$
ccubic in $x$
dan identity

ব্যাখ্যা

Using $(x+1)^3-(x-1)^3=6x^2+2$ and $(x+1)^2-(x-1)^2=4x$ , the expression reduces to $\frac{6x^2+2}{4x}=1$ . Cross-multiplying gives $6x^2-4x+2=0$ , a quadratic in $x$ .

এই অধ্যায়ের আরও প্রশ্ন

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Equations in One Variable — সব প্রশ্ন দেখুন (170টি) →

Solution set of $\dfrac{(x + 1)^3 - (x - 1)^3}{(x + 1)^2 - (x - 1)^2} = 1$ comes from—

asimplifying to

\dfrac{6x^2 + 2}{4x} = 1

, then quadratic in

x

blinear in

x

ccubic in

x

dan identity

ব্যাখ্যা

Using $(x+1)^3-(x-1)^3=6x^2+2$ and $(x+1)^2-(x-1)^2=4x$ , the expression reduces to $\frac{6x^2+2}{4x}=1$ . Cross-multiplying gives $6x^2-4x+2=0$ , a quadratic in $x$ .

Solution set of (x+1)3−(x−1)3(x+1)2−(x−1)2=1\dfrac{(x + 1)^3 - (x - 1)^3}{(x + 1)^2 - (x - 1)^2} = 1(x+1)2−(x−1)2(x+1)3−(x−1)3​=1 comes from—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Solution set of (x+1)3−(x−1)3(x+1)2−(x−1)2=1\dfrac{(x + 1)^3 - (x - 1)^3}{(x + 1)^2 - (x - 1)^2} = 1(x+1)2−(x−1)2(x+1)3−(x−1)3​=1 comes from—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Solution set of $\dfrac{(x + 1)^3 - (x - 1)^3}{(x + 1)^2 - (x - 1)^2} = 1$ comes from—

Solution set of $\dfrac{(x + 1)^3 - (x - 1)^3}{(x + 1)^2 - (x - 1)^2} = 1$ comes from—