C-05-Q099mediumsingle_mcq

Solution set of $x - 4 = \dfrac{x - 4}{x}$ is—

a $\{1\}$
b $\{4\}$
c $\{1, 4\}$
d $\{0, 4\}$

ব্যাখ্যা

Multiplying through by $x$ gives $x(x-4)=x-4$ , so $(x-4)(x-1)=0$ . This yields $x=4$ or $x=1$ , and since neither makes the denominator zero, both are valid: $\{1,4\}$ .

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Equations in One Variable — সব প্রশ্ন দেখুন (170টি) →

Solution set of $x - 4 = \dfrac{x - 4}{x}$ is—

\{1\}

\{4\}

\{1, 4\}

\{0, 4\}

ব্যাখ্যা

Multiplying through by $x$ gives $x(x-4)=x-4$ , so $(x-4)(x-1)=0$ . This yields $x=4$ or $x=1$ , and since neither makes the denominator zero, both are valid: $\{1,4\}$ .

Solution set of x−4=x−4xx - 4 = \dfrac{x - 4}{x}x−4=xx−4​ is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Solution set of x−4=x−4xx - 4 = \dfrac{x - 4}{x}x−4=xx−4​ is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Solution set of $x - 4 = \dfrac{x - 4}{x}$ is—

Solution set of $x - 4 = \dfrac{x - 4}{x}$ is—