C-05-Q100mediumsingle_mcqFrom (x+ax−a)2−5(x+ax−a)+6=0\left(\dfrac{x + a}{x - a}\right)^2 - 5\left(\dfrac{x + a}{x - a}\right) + 6 = 0(x−ax+a)2−5(x−ax+a)+6=0, with y=x+ax−ay = \dfrac{x + a}{x - a}y=x−ax+a, the values of yyy are—a1,61, 61,6b−2,−3-2, -3−2,−3c2,32, 32,3d0,50, 50,5ব্যাখ্যাSubstituting yyy gives y2−5y+6=0y^2-5y+6=0y2−5y+6=0, which factors as (y−2)(y−3)=0(y-2)(y-3)=0(y−2)(y−3)=0. Hence y=2y=2y=2 or y=3y=3y=3.