C-05-Q098mediumsingle_mcqSolution set of y2=3 yy^2 = \sqrt{3}\, yy2=3y is—a{0,3}\{0, \sqrt{3}\}{0,3}bব্যাখ্যাRearranging gives y2−3 y=0y^2-\sqrt{3}\,y=0y2−3y=, so . Thus or , giving the solution set .