C-10-Q146mediumsingle_mcq

From $\cos 60^\circ = \dfrac{7}{\ell}$ , the broken piece $\ell$ equals—

a $7$ m
b $14$ m
c $7\sqrt{3}$ m
d $\dfrac{7}{\sqrt{3}}$ m

ব্যাখ্যা

Here $7$ m is the adjacent side and $\ell$ the hypotenuse, so $\cos 60^\circ=\dfrac{7}{\ell}$ ; with $\cos 60^\circ=\dfrac{1}{2}$ , this gives $\ell=14$ m.

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Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

From $\cos 60^\circ = \dfrac{7}{\ell}$ , the broken piece $\ell$ equals—

7

14

7\sqrt{3}

\dfrac{7}{\sqrt{3}}

ব্যাখ্যা

Here $7$ m is the adjacent side and $\ell$ the hypotenuse, so $\cos 60^\circ=\dfrac{7}{\ell}$ ; with $\cos 60^\circ=\dfrac{1}{2}$ , this gives $\ell=14$ m.

From cos⁡60∘=7ℓ\cos 60^\circ = \dfrac{7}{\ell}cos60∘=ℓ7​, the broken piece ℓ\ellℓ equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From cos⁡60∘=7ℓ\cos 60^\circ = \dfrac{7}{\ell}cos60∘=ℓ7​, the broken piece ℓ\ellℓ equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From $\cos 60^\circ = \dfrac{7}{\ell}$ , the broken piece $\ell$ equals—

From $\cos 60^\circ = \dfrac{7}{\ell}$ , the broken piece $\ell$ equals—