C-10-Q153mediumsingle_mcqtan30∘⋅tan60∘\tan 30^\circ \cdot \tan 60^\circtan30∘⋅tan60∘ equals—a111b3\sqrt{3}3ব্যাখ্যাSince tan30∘=13\tan 30^\circ = \frac{1}{\sqrt{3}}tan30∘=3 and , their product is . These two angles are complementary, and .