C-10-Q155mediumsingle_mcqsin245∘+cos245∘\sin^2 45^\circ + \cos^2 45^\circsin245∘+cos245∘ equals—a12\dfrac{1}{2}21b111c2\sqrt{2}2d000ব্যাখ্যাThis is the Pythagorean identity sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1sin2θ+cos2θ=1, which holds for every angle, including 45∘45^\circ45∘. Numerically, (12)2+(12)2=12+12=1\left(\frac{1}{\sqrt{2}}\right)^2 + \left(\frac{1}{\sqrt{2}}\right)^2 = \frac{1}{2} + \frac{1}{2} = 1(21)2+(21)2=21+21=1.