C-10-Q129mediumsingle_mcq

Substituting and solving $\ell\!\left(\dfrac{\sqrt{3}}{2} + 1\right) = 64$ gives $\ell = ?$

a $\dfrac{128}{2 + \sqrt{3}}$ m
b $\dfrac{64}{\sqrt{3} + 1}$ m
c $32(2 - \sqrt{3})$ m
d $64\sqrt{3}$ m

ব্যাখ্যা

Substituting $h_1=\ell\sin 60^\circ=\ell\dfrac{\sqrt{3}}{2}$ into $h_1+\ell=64$ gives $\ell\!\left(\dfrac{\sqrt{3}}{2}+1\right)=64$ . Multiplying through by $2$ yields $\ell=\dfrac{128}{2+\sqrt{3}}$ m.

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Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

Substituting and solving $\ell\!\left(\dfrac{\sqrt{3}}{2} + 1\right) = 64$ gives $\ell = ?$

\dfrac{128}{2 + \sqrt{3}}

\dfrac{64}{\sqrt{3} + 1}

32(2 - \sqrt{3})

64\sqrt{3}

Substituting and solving ℓ ⁣(32+1)=64\ell\!\left(\dfrac{\sqrt{3}}{2} + 1\right) = 64ℓ(23​​+1)=64 gives ℓ=?\ell = ?ℓ=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Substituting and solving ℓ ⁣(32+1)=64\ell\!\left(\dfrac{\sqrt{3}}{2} + 1\right) = 64ℓ(23​​+1)=64 gives ℓ=?\ell = ?ℓ=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Substituting and solving $\ell\!\left(\dfrac{\sqrt{3}}{2} + 1\right) = 64$ gives $\ell = ?$

Substituting and solving $\ell\!\left(\dfrac{\sqrt{3}}{2} + 1\right) = 64$ gives $\ell = ?$