C-10-Q128mediumsingle_mcq

The vertical drop of the break equals the standing piece, giving $h_1 = ?$

a $\ell \cdot \cos 60^\circ$
b $\ell \cdot \sin 60^\circ$
c $\ell \cdot \tan 60^\circ$
d $\ell$

ব্যাখ্যা

The slanting piece $\ell$ makes a $60^\circ$ angle, so its vertical height is $\ell\sin 60^\circ$ , which equals the standing piece. Hence $h_1=\ell\sin 60^\circ$ .

এই অধ্যায়ের আরও প্রশ্ন

C-10-Q129Substituting and solving gives
C-10-Q130The approximate length of the broken piece is—
C-10-Q131The rationalized form equals—
C-10-Q132With standing piece and slanting piece touching ground at where m and , gives
C-10-Q133Numerically is approximately—
C-10-Q134From , the slanting piece equals—
C-10-Q135The total height of the original tree is—
C-10-Q136Approximately, the tree was—
C-10-Q137The other name of the horizontal line (geo-line) is—
C-10-Q138In a figure where and lie on a horizontal line above, and on a horizontal line below, and is the transversal,

Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

The vertical drop of the break equals the standing piece, giving $h_1 = ?$

\ell \cdot \cos 60^\circ

\ell \cdot \sin 60^\circ

\ell \cdot \tan 60^\circ

\ell

ব্যাখ্যা

The slanting piece $\ell$ makes a $60^\circ$ angle, so its vertical height is $\ell\sin 60^\circ$ , which equals the standing piece. Hence $h_1=\ell\sin 60^\circ$ .

The vertical drop of the break equals the standing piece, giving h1=?h_1 = ?h1​=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The vertical drop of the break equals the standing piece, giving h1=?h_1 = ?h1​=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The vertical drop of the break equals the standing piece, giving $h_1 = ?$

The vertical drop of the break equals the standing piece, giving $h_1 = ?$