C-10-Q134mediumsingle_mcq

From $\sin 30^\circ = \dfrac{12}{CD}$ , the slanting piece $CD$ equals—

With $\sin 30^\circ=\dfrac{12}{CD}$ and $\sin 30^{\circ} = \frac{}{}$ , solving gives m.

134/160

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6

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2

\sin 30^\circ=\dfrac{1}{2}

sin 3 0^{\circ} = \frac{1}{2}

CD=\dfrac{12}{1/2}=24