C-10-Q134mediumsingle_mcqFrom sin30∘=12CD\sin 30^\circ = \dfrac{12}{CD}sin30∘=CD12, the slanting piece CDCDCD equals—a121212 mb242424 mc363636 md666 mব্যাখ্যাWith sin30∘=12CD\sin 30^\circ=\dfrac{12}{CD}sin30∘=CD12 and sin30∘=12\sin 30^\circ=\dfrac{1}{2}sin30∘=21, solving gives CD=121/2=24CD=\dfrac{12}{1/2}=24CD=1/212=24 m.