C-10-Q098mediumsingle_mcq

With height $26$ m and elevation $30^\circ$ from a point, the ground distance $d$ satisfies—

a $d = 26 \cdot \tan 30^\circ$
b $d = \dfrac{26}{\tan 30^\circ}$
c $d = 26 \cdot \sin 30^\circ$
d $d = \dfrac{26}{\sin 30^\circ}$

ব্যাখ্যা

Here the height $26$ m is the side opposite the $30^\circ$ angle and $d$ is the adjacent side, so $\tan 30^\circ = \frac{26}{d}$ . Rearranging gives $d = \frac{26}{\tan 30^\circ}$ .

এই অধ্যায়ের আরও প্রশ্ন

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Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

With height $26$ m and elevation $30^\circ$ from a point, the ground distance $d$ satisfies—

d = 26 \cdot \tan 30^\circ

d = \dfrac{26}{\tan 30^\circ}

d = 26 \cdot \sin 30^\circ

d = \dfrac{26}{\sin 30^\circ}

ব্যাখ্যা

Here the height $26$ m is the side opposite the $30^\circ$ angle and $d$ is the adjacent side, so $\tan 30^\circ = \frac{26}{d}$ . Rearranging gives $d = \frac{26}{\tan 30^\circ}$ .

With height 262626 m and elevation 30∘30^\circ30∘ from a point, the ground distance ddd satisfies—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With height 262626 m and elevation 30∘30^\circ30∘ from a point, the ground distance ddd satisfies—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With height $26$ m and elevation $30^\circ$ from a point, the ground distance $d$ satisfies—

With height $26$ m and elevation $30^\circ$ from a point, the ground distance $d$ satisfies—