C-10-Q102mediumsingle_mcq

With base distance $20$ m and elevation $60^\circ$ , the height $h$ equals—

a $20 \cdot \tan 60^\circ$
b $\dfrac{20}{\tan 60^\circ}$
c $20 \cdot \cos 60^\circ$
d $20 \cdot \sin 60^\circ$

ব্যাখ্যা

With base $20$ m as the adjacent side and height $h$ opposite the $60^\circ$ angle, $\tan 60^\circ = \frac{h}{20}$ . Solving gives $h = 20\tan 60^\circ$ .

এই অধ্যায়ের আরও প্রশ্ন

C-10-Q103m is approximately—
C-10-Q104With the same m base distance, if the elevation were , the height would be—
C-10-Q105With ladder m and ground angle , the height of the wall equals—
C-10-Q106in simplest surd form equals—
C-10-Q107The approximate wall height is—
C-10-Q108From the top of a house, the angle of depression to a point on the ground m from the foot is . The angle of el
C-10-Q109The equation gives
C-10-Q110is approximately—
C-10-Q111After rationalization, becomes—
C-10-Q112Initial elevation of tower top is at with . Then equals—

Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

With base distance $20$ m and elevation $60^\circ$ , the height $h$ equals—

20 \cdot \tan 60^\circ

\dfrac{20}{\tan 60^\circ}

20 \cdot \cos 60^\circ

20 \cdot \sin 60^\circ

ব্যাখ্যা

With base $20$ m as the adjacent side and height $h$ opposite the $60^\circ$ angle, $\tan 60^\circ = \frac{h}{20}$ . Solving gives $h = 20\tan 60^\circ$ .

With base distance 202020 m and elevation 60∘60^\circ60∘, the height hhh equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With base distance 202020 m and elevation 60∘60^\circ60∘, the height hhh equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With base distance $20$ m and elevation $60^\circ$ , the height $h$ equals—

With base distance $20$ m and elevation $60^\circ$ , the height $h$ equals—