C-10-Q105: With ladder $18$ m and ground angle $45^\circ$, the height of the wall… | প্রশ্ন করি

হোম›নবম-দশম শ্রেণি›English Version›Mathematics›Chapter 10: Distance and Elevation›C-10-Q105

C-10-Q105mediumsingle_mcq

With ladder $18$ m and ground angle $45^\circ$ , the height of the wall equals—

a $18 \cdot \cos 45^\circ$
b $18 \cdot \sin 45^\circ$

ব্যাখ্যা

The ladder of $18$ m is the hypotenuse, and the wall height is the side opposite the $45^\circ$ angle, so $\sin 45^\circ = \frac{\text{height}}{18}$ . Therefore the height is .

105/160

এই অধ্যায়ের আরও প্রশ্ন

C-10-Q106in simplest surd form equals—
C-10-Q107The approximate wall height is—
C-10-Q108From the top of a house, the angle of depression to a point on the ground m from the foot is . The angle of el
C-10-Q109The equation gives
C-10-Q110is approximately—
C-10-Q111After rationalization, becomes—
C-10-Q112Initial elevation of tower top is at with . Then equals—
C-10-Q113After moving m back to point where elevation is , equals—
C-10-Q114Combining the two equations gives

∘

18 \cdot \tan 45^\circ

\dfrac{18}{\sin 45^\circ}

18height

18\sin 45^\circ

C-10-Q115

Then equals—

Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

With ladder 181818 m and ground angle 45∘45^\circ45∘, the height of the wall equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With ladder $18$ m and ground angle $45^\circ$ , the height of the wall equals—