C-08-Q100mediumsingle_mcq

Since $\angle BOD = \angle BAO + \angle ABO = 2\angle BAO$ , similarly $\angle COD$ equals—

a $\angle CAO$
b $2\angle CAO$
c $\frac{1}{2}\angle CAO$
d $\angle BAO$

ব্যাখ্যা

By the same exterior-angle and isosceles-triangle argument applied to $\triangle AOC$ , the exterior angle $\angle COD = \angle CAO + \angle ACO = 2\angle CAO$ , mirroring the result obtained for $\angle BOD$ .

এই অধ্যায়ের আরও প্রশ্ন

C-08-Q101Adding the two relations gives
C-08-Q102The Work box accompanying Theorem 20 asks to prove the theorem when—
C-08-Q103The angle standing on an arc of the circle equals— the angle subtended by the arc at the centre.
C-08-Q104Angles in a circle standing on the same arc are—
C-08-Q105In Theorem 21, and standing on arc are equal because each equals—
C-08-Q106If two angles inscribed in a circle subtend the same chord and lie on the same side of it, they are—
C-08-Q107The fact "angles in the same segment are equal" is a direct consequence of—
C-08-Q108In Theorem 21, the central angle subtended by arc is referenced to convert two inscribed angles into—
C-08-Q109The angle inscribed in a semicircle is—
C-08-Q110In Theorem 22, the central angle on diameter equals—

Circle — সব প্রশ্ন দেখুন (231টি) →

Since $\angle BOD = \angle BAO + \angle ABO = 2\angle BAO$ , similarly $\angle COD$ equals—

\angle CAO

2\angle CAO

\frac{1}{2}\angle CAO

\angle BAO

Since ∠BOD=∠BAO+∠ABO=2∠BAO\angle BOD = \angle BAO + \angle ABO = 2\angle BAO∠BOD=∠BAO+∠ABO=2∠BAO, similarly ∠COD\angle COD∠COD equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Since ∠BOD=∠BAO+∠ABO=2∠BAO\angle BOD = \angle BAO + \angle ABO = 2\angle BAO∠BOD=∠BAO+∠ABO=2∠BAO, similarly ∠COD\angle COD∠COD equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Since $\angle BOD = \angle BAO + \angle ABO = 2\angle BAO$ , similarly $\angle COD$ equals—

Since $\angle BOD = \angle BAO + \angle ABO = 2\angle BAO$ , similarly $\angle COD$ equals—