C-08-Q101mediumsingle_mcq

Adding the two relations gives $\angle BOC = \dotsb$

a $\angle BAC$
b $2\angle BAC$
c $\frac{1}{2}\angle BAC$
d $\angle BAO + \angle CAD$

ব্যাখ্যা

Adding $\angle BOD = 2\angle BAO$ and $\angle COD = 2\angle CAO$ gives $\angle BOC = 2(\angle BAO + \angle CAO) = 2\angle BAC$ , which is exactly the statement of Theorem 20.

এই অধ্যায়ের আরও প্রশ্ন

C-08-Q102The Work box accompanying Theorem 20 asks to prove the theorem when—
C-08-Q103The angle standing on an arc of the circle equals— the angle subtended by the arc at the centre.
C-08-Q104Angles in a circle standing on the same arc are—
C-08-Q105In Theorem 21, and standing on arc are equal because each equals—
C-08-Q106If two angles inscribed in a circle subtend the same chord and lie on the same side of it, they are—
C-08-Q107The fact "angles in the same segment are equal" is a direct consequence of—
C-08-Q108In Theorem 21, the central angle subtended by arc is referenced to convert two inscribed angles into—
C-08-Q109The angle inscribed in a semicircle is—
C-08-Q110In Theorem 22, the central angle on diameter equals—
C-08-Q111Since and is a straight angle, equals—

Circle — সব প্রশ্ন দেখুন (231টি) →

Adding the two relations gives $\angle BOC = \dotsb$

\angle BAC

2\angle BAC

\frac{1}{2}\angle BAC

\angle BAO + \angle CAD

ব্যাখ্যা

Adding $\angle BOD = 2\angle BAO$ and $\angle COD = 2\angle CAO$ gives $\angle BOC = 2(\angle BAO + \angle CAO) = 2\angle BAC$ , which is exactly the statement of Theorem 20.

Adding the two relations gives ∠BOC=⋯\angle BOC = \dotsb∠BOC=⋯

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Adding the two relations gives ∠BOC=⋯\angle BOC = \dotsb∠BOC=⋯

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

Adding the two relations gives $\angle BOC = \dotsb$

Adding the two relations gives $\angle BOC = \dotsb$