C-08-Q099mediumsingle_mcq

In $\triangle AOB$ , $OA = OB$ implies $\angle BAO = \angle ABO$ because—

aall triangles are isosceles
bbase angles of an isosceles triangle are equal
cof SAS
dof RHS

ব্যাখ্যা

$OA$ and $OB$ are both radii, so $\triangle AOB$ is isosceles; the base angles opposite the equal sides are therefore equal, giving $\angle BAO = \angle ABO$ .

এই অধ্যায়ের আরও প্রশ্ন

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Circle — সব প্রশ্ন দেখুন (231টি) →

In $\triangle AOB$ , $OA = OB$ implies $\angle BAO = \angle ABO$ because—

aall triangles are isosceles

bbase angles of an isosceles triangle are equal

cof SAS

dof RHS

ব্যাখ্যা

$OA$ and $OB$ are both radii, so $\triangle AOB$ is isosceles; the base angles opposite the equal sides are therefore equal, giving $\angle BAO = \angle ABO$ .

In △AOB\triangle AOB△AOB, OA=OBOA = OBOA=OB implies ∠BAO=∠ABO\angle BAO = \angle ABO∠BAO=∠ABO because—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In △AOB\triangle AOB△AOB, OA=OBOA = OBOA=OB implies ∠BAO=∠ABO\angle BAO = \angle ABO∠BAO=∠ABO because—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In $\triangle AOB$ , $OA = OB$ implies $\angle BAO = \angle ABO$ because—

In $\triangle AOB$ , $OA = OB$ implies $\angle BAO = \angle ABO$ because—