C-11-Q173mediumsingle_mcqIf a+ba−b=73\dfrac{a+b}{a-b} = \dfrac{7}{3}a−ba+b=37, then ab=\dfrac{a}{b} =ba=a52\dfrac{5}{2}25b73\dfrac{7}{3}37c41\dfrac{4}{1}14d104\dfrac{10}{4}410ব্যাখ্যাApplying componendo-dividendo to a+ba−b=73\dfrac{a+b}{a-b}=\dfrac{7}{3}a−ba+b=37 gives ab=7+37−3=104=52\dfrac{a}{b}=\dfrac{7+3}{7-3}=\dfrac{10}{4}=\dfrac{5}{2}ba=7−37+3=410=25.