C-11-Q171mediumsingle_mcq

If $\dfrac{a+b}{b+c} = \dfrac{4}{5}$ and $a:b = b:c$ , then $\dfrac{a}{c} =$

a $\dfrac{16}{25}$
b $\dfrac{4}{5}$
c $\dfrac{5}{4}$
d $\dfrac{2}{5}$

ব্যাখ্যা

Since $a:b=b:c$ , the terms are $a, ar, ar^2$ , and $\dfrac{a+b}{b+c}=\dfrac{1}{r}=\dfrac{4}{5}$ gives $r=\dfrac{5}{4}$ . Then $\dfrac{a}{c}=\dfrac{1}{r^2}=\dfrac{16}{25}$ .

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Algebraic Ratio and Proportion — সব প্রশ্ন দেখুন (180টি) →

If $\dfrac{a+b}{b+c} = \dfrac{4}{5}$ and $a:b = b:c$ , then $\dfrac{a}{c} =$

\dfrac{16}{25}

\dfrac{4}{5}

\dfrac{5}{4}

\dfrac{2}{5}

ব্যাখ্যা

Since $a:b=b:c$ , the terms are $a, ar, ar^2$ , and $\dfrac{a+b}{b+c}=\dfrac{1}{r}=\dfrac{4}{5}$ gives $r=\dfrac{5}{4}$ . Then $\dfrac{a}{c}=\dfrac{1}{r^2}=\dfrac{16}{25}$ .

If a+bb+c=45\dfrac{a+b}{b+c} = \dfrac{4}{5}b+ca+b​=54​ and a:b=b:ca:b = b:ca:b=b:c, then ac=\dfrac{a}{c} =ca​=

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

If a+bb+c=45\dfrac{a+b}{b+c} = \dfrac{4}{5}b+ca+b​=54​ and a:b=b:ca:b = b:ca:b=b:c, then ac=\dfrac{a}{c} =ca​=

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

If $\dfrac{a+b}{b+c} = \dfrac{4}{5}$ and $a:b = b:c$ , then $\dfrac{a}{c} =$

If $\dfrac{a+b}{b+c} = \dfrac{4}{5}$ and $a:b = b:c$ , then $\dfrac{a}{c} =$