C-11-Q099mediumsingle_mcqIf a:b=c:da:b = c:da:b=c:d, then (2a+b)2(2c+d)2\dfrac{(2a + b)^2}{(2c + d)^2}(2c+d)2(2a+b)2 equals—a(2a−b)2(2c−d)2\dfrac{(2a-b)^2}{(2c-d)^2}(2c−d)2(2a−b)ব্যাখ্যাWith ac=bd=k\frac{a}{c}=\frac{b}{d}=kca=db, we have and , so . All three listed expressions are equal.