C-11-Q108mediumsingle_mcq

From $x:y = 2:1$ and $y:z = 2:1$ , the relation $y^2 = zx$ shows that $x, y, z$ are in—

aarithmetic progression
bcontinued proportion
charmonic progression
dequal

ব্যাখ্যা

From $x:y:z=4:2:1$ , we get $y^2=2^2=4$ and $zx=1\times4=4$ , so $y^2=zx$ . This relation $y^2=zx$ is the condition for $x, y, z$ to be in continued proportion.

এই অধ্যায়ের আরও প্রশ্ন

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Algebraic Ratio and Proportion — সব প্রশ্ন দেখুন (180টি) →

From $x:y = 2:1$ and $y:z = 2:1$ , the relation $y^2 = zx$ shows that $x, y, z$ are in—

aarithmetic progression

bcontinued proportion

charmonic progression

dequal

ব্যাখ্যা

From $x:y:z=4:2:1$ , we get $y^2=2^2=4$ and $zx=1\times4=4$ , so $y^2=zx$ . This relation $y^2=zx$ is the condition for $x, y, z$ to be in continued proportion.

From x:y=2:1x:y = 2:1x:y=2:1 and y:z=2:1y:z = 2:1y:z=2:1, the relation y2=zxy^2 = zxy2=zx shows that x,y,zx, y, zx,y,z are in—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From x:y=2:1x:y = 2:1x:y=2:1 and y:z=2:1y:z = 2:1y:z=2:1, the relation y2=zxy^2 = zxy2=zx shows that x,y,zx, y, zx,y,z are in—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

From $x:y = 2:1$ and $y:z = 2:1$ , the relation $y^2 = zx$ shows that $x, y, z$ are in—

From $x:y = 2:1$ and $y:z = 2:1$ , the relation $y^2 = zx$ shows that $x, y, z$ are in—