C-11-Q065mediumsingle_mcqIf a:b=b:ca:b = b:ca:b=b:c, then a+bb+c\dfrac{a+b}{b+c}b+ca+b equals—aac\sqrt{\dfrac{a}{c}}cabac\dfrac{a}{c}cacca\dfrac{c}{a}acdca\sqrt{\dfrac{c}{a}}acব্যাখ্যাWith ab=bc=k\dfrac{a}{b}=\dfrac{b}{c}=kba=cb=k, we have a+bb+c=bk+ckb+c=k\dfrac{a+b}{b+c}=\dfrac{bk+ck}{b+c}=kb+ca+b=b+cbk+ck=k. Since ac=k2\dfrac{a}{c}=k^2ca=k2, it follows that k=ack=\sqrt{\dfrac{a}{c}}k=ca.