C-11-Q069mediumsingle_mcqIf x2=y3=z5\dfrac{x}{2} = \dfrac{y}{3} = \dfrac{z}{5}2x=3y=5z, then x+y+z2+3+5\dfrac{x+y+z}{2+3+5}2+3+5x+y+z equals—ax2\dfrac{x}{2}2xb110\dfrac{1}{10}101cx+y+zx\dfrac{x+y+z}{x}xx+y+zd000ব্যাখ্যাBy the sum rule, x+y+z2+3+5\dfrac{x+y+z}{2+3+5}2+3+5x+y+z equals the common ratio x2=y3=z5\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{5}2x=3y=5z. Substituting x=2k, y=3k, z=5kx=2k,\ y=3k,\ z=5kx=2k, y=3k, z=5k gives 10k10=k=x2\dfrac{10k}{10}=k=\dfrac{x}{2}1010k=k=2x.